Electric Motor Academy·10 min read·
intermediate

Back-EMF explained

Why a spinning motor fights the voltage that is driving it — and why that matters for control.

You'll learn
  • Explain back-emf explained at engineering level
  • Read the numbers that define the behaviour
  • Apply the idea to a real drive unit

Overview

As soon as a motor's rotor starts turning, it generates its own voltage that opposes the supply — this is back-EMF, and it governs almost everything about how a motor behaves at speed.

In depth

Formula
E = k_e × ω

Back-EMF is proportional to rotor speed, scaled by the motor's back-EMF constant, which itself depends on magnet flux and winding turns.

Example: A motor with k_e = 0.1 V·s/rad spinning at 1,500 rad/s (≈14,300 rpm) generates 150 V of back-EMF.

Why current falls as speed rises

The current driving torque is proportional to the difference between the applied voltage and the back-EMF, divided by winding resistance and inductance effects. As speed rises, back-EMF climbs toward the DC-link voltage, squeezing the available voltage margin and therefore the current — and the torque — that can be delivered.

Uncontrolled generation

If an inverter loses control of a spinning permanent-magnet motor at high speed, its uncontrolled back-EMF can exceed the DC bus rating — a real fault mode engineers must design safety systems around.

Key takeaways

Remember this
  • Back-EMF is proportional to rotor speed and opposes the drive voltage.
  • Rising back-EMF is what limits current and torque as speed increases.
  • Base speed is defined by back-EMF approaching the available bus voltage.
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